Question

Find the area of the region.
Inside r = 2a cos(θ) and outside r = a

Answer 1

\[\int_{0}^{2\pi}\int_{2a * cos(\theta)}^{a} r dr d\theta\]

Answer 2

????

Answer 3

what??

Answer 4

What does that even mean?

Answer 5

that's double integral

Answer 6

how do you go about that? Never have seen that form before....

Answer 7

@experimentX

Answer 8

\[\int_{0}^{2\pi}\int_{2a * cos(\theta)}^{a} r dr d\theta\]

\[\int_{0}^{2\pi}|_{2a * cos(\theta)}^{a} r^2/2 d\theta\]

\[\int_{0}^{2\pi}(a)^2-(2a cos(\theta))^2/2 d\theta\]

Answer 9

you integrate it again, this time w.r.t theta

Answer 10

hmm

Answer 11

wow OS crashed hard...