Question

Calendar concept ..

Answer 1

@annas and @angela210793

Answer 2

for example : november 9 , 1991

Answer 3

1990 = 1600 + 300 + 0

Answer 4

odd days in 1600 = 0 and in 300 = 1 .. hence we get total odd days in 1900 = 1

Answer 5

now calculate the total number of days from 1.1.1991 to 9.11.1991

Answer 6

since 1991 is not a leap year hence we have days in february = 28

31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 9 = 313

divide that by 7

we get remainder = 5

hence total number of odd days = 1 + 5 = 6

Answer 7

Monday Tuesday Wednesday Thursday Friday Saturday Sunday
1 2 3 4 5 6 7

total number of odd days = 6

hence on 9 november 1991 it was saturday

Answer 8

@annas right?

Answer 9

Very niice :D

Answer 10

yes it is a very nice process also

Answer 11

useful process

Answer 12

O.o i m shocked ... but awesome

Answer 13

:) thanks

Answer 14

we can make a computer program on that

Answer 15

logic

Answer 16

yes .. can u?

Answer 17

i can try , i have to make an algorithm on that first. i'll try as soon as my website work is done

Answer 18

oh k

Answer 19

but i didnt get.......

Answer 20

what is ur date of birth .. i will take urs as an example

Answer 21

15 july 1992

Answer 22

ok so first of all :
1992 = 1600 + 300 + 2 right?

Answer 23

wait always we have to break into 1600 +........so on

Answer 24

yes it becomes easy

Answer 25

wait we will take 1991 here:

1991 = 1600+300+1

1600 = 0 odd days
300 = 1 odd day
1 = 1 odd day

now calculate the number of days from 1.1.1992 to 15.07.1992

31+29+31+30+31+30+15 = 197
divide 197 by 7

remainder = 1

hence total number of odd days = 1 + 1 + 1 = 3

Answer 26

hence the day on 15 july 1992 = wednesday

Answer 27

got it ? @nitz

Answer 28

wait...

Answer 29

300........1 odd day??

Answer 30

yes

Answer 31

Number of odd days in 300 years = (5 x 3) =15/7 = remainder = 1 odd day.

Answer 32

we can write 300 = (100)*3

number of odd days in 100 = 5 and hence in 300 it will be 5*3 = 15 / 7 remainder = 1

Answer 33

got it?

Answer 34

100 years = 76 ordinary years + 24 leap years

= (76 x 1 + 24 x 2) odd days = 124 odd days.

= (17 weeks + days) 5 odd days.

Number of odd days in 100 years = 5.

Answer 35

leave it ........i am getting confused
anyways thank you,,,,,,,

Answer 36

http://www.indiabix.com/aptitude/calendar/formulas

Answer 37

this is a confusing topic
no problem

Answer 38

i learnt some simple tricks like 85^2,125^2......

Answer 39

85^2 = (90-5)^2 = 8100+25-900 = 8125-900 = 7225

Answer 40

well wait lemme show u the shortcut one also

Answer 41

\[85^{2}=?\]
firstly mutiply last two :5*5=25
then multiply first digit that is 8*9=72
so 7225

Answer 42

:D right

Answer 43

i have multiplied first digit with a digit exceeding it....8*9=72

Answer 44

125^2 = 5^2
12*13=156

15625 = 125^2

Answer 45

ya....

Answer 46

even for 11....
say 49*11 we have
9 as it is
4+9=13
i carry off and4+1=5
so 539

Answer 47

...i dont get it...

Answer 48

should i give u another example?

Answer 49

@lgbasallote so lemme take this as an example :

what is the day on 06-8-2012 ?

ok?

Answer 50

yeah sure

Answer 51

ok so 2011 = 1600 + 300 + 111 right ?

Answer 52

but you're looking for 2012...

Answer 53

yes but we will calculate odd days in 2011 years and then from 01-08-2012 to 06-08-2012

Answer 54

since 2012 is not a complete year hence we are taking 2011 there. . ok?

Answer 55

go on

Answer 56

wait i am making it soo long sorry

Answer 57

ok so .. 2011 = 1600 + 300 + 100+10+1

odd days in 1600 = 0 , in 300 = 1 and in 111= 5

now : count the total number of days from 1.1.2012 to 6.8.2012 :

31+29+31+30+31+30+31+6 = 219

divide 219 by 7 : we get remainder as 2

hence total number of odd days : 5 + 1 + 2 = 6 + 2 = 8

now : 8 days / 7 = remainder = 1
hence finally 1 odd day that denotes that the day on 06.08.2012 is monday

monday

Answer 58

Made it short :D ..

well do you know the exact meaning of odd days?

Answer 59

well do you know understand what this concept is?

any more questions

Answer 60

what do you mean 0 odd days in 1600; 1 in 300 and 5 in 111

Answer 61

hint :

1 ordinary year = 52 weeks + 1 day

hence that 1 day is odd day =1

Answer 62

@mathslover can u expl this to me

Answer 63

No problem what is ur date of birth ?

Answer 64

ok . so
1995 = 1600 + 300 + 5

right?

Answer 65

oops wait it is :

1995 = 1600 + 300 + 95 right?

Answer 66

it is 1996

Answer 67

1996 is not a full year .. hence we will take 1995 there .. ok?

Answer 68

wat do u mean by full year

Answer 69

wat do u mean by full year

Answer 70

@mathslover

Answer 71

full year means that : 365 days

in 1996 you dont have 365 days as ur birthday is on 11 - 03 .. got it?

Answer 72

ok

Answer 73

now

no. of odd days in 1600 =0 in 300 = 1 and in 95 =6

count days from 1.1.1996 to 11.03.1996

31+29+11 = 71

71/7 = remainder = 1

total odd days = 6+1+1 = 8

hence on 11.03.1996 it was monday

Answer 74

95/4 = 23 ..

hence 95 years = 23 leap years + 72 ordinary years

odd days in 95 years = 23*2 + 72*1=46+72 = 118

118/7 = remainder = 6

Answer 75

got it @Yahoo! ?

Answer 76

u r correct....

Answer 77

thanks

Answer 78

@mathslover Any video on this topic

Answer 79

well not yet but lemme check it

Answer 80

sorry no .. @Yahoo!

http://www.indiabix.com/aptitude/calendar/

prefer this

Answer 81

good question :

for example :

1 ordinary year has 365 days

there are totally 52 weeks and 1 day ..


that 1 day is called odd day

Answer 82

Can you explain why the mayan calendar says the world is going to end this year?

Answer 83

well that are superstitions , only mayan calendar can explain sorry

Answer 84

@RyanL. It has been assumed that the world will end just because 2012 is the last year mentioned in Mayan Calendar.