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Solve by factoring: x2+4x+3=0
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\[\large{x^2+4x+3=0}\] \[\large{x^2+x+3x+3=0}\] right?
yes
now: \[\large{x(x+1)+3(x+1)=0}\] \[\large{(x+3)(x+1)=0}\] right?
now either x+3 = 0 or x + 1 = 0 can you solve these 2 eqn now?
yes, i just subtract 3 and get x=-3 and subtract 1 and get x=-1 , right?
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right very right ..
good ..
so the answer is x= -3 &-1
yes
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