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OpenStudy (anonymous):
Factor: 36x2 − 1
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Parth (parthkohli):
More like \((6x)^2 - (1)^2\) right?
Parth (parthkohli):
Do you know how you can factor difference of squares?
OpenStudy (anonymous):
(6x -1) (6x +1)
OpenStudy (anonymous):
36x^2 and 1 are perfect squares, so this is a difference of squares (6x+1)(6x-1)
OpenStudy (anonymous):
no
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Parth (parthkohli):
\[(a + b)(a - b) = a^2 - b^2\]Here, \(a = 6x\) and \(b = 1\)
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