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let \[a★b = ab + a + b\]So,How many consecutive nines are there at the end of : \[1★(2★(3 ★(4★...(99★100))))\]
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it is equal to factorial 100
6*4
6 zeros in 25!
i think there is a zero counting theorem though ...
yep
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it seems that i have forgotten it though
its 24 i think
\[\lfloor \frac{101}{5} \rfloor+\lfloor \frac{101}{25} \rfloor=24\]
it is 24 ... i checked from WA. yep ... that's the one ...
|dw:1344192556899:dw|
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