Question

Arectangle has a perimeter of 30m. The length is 10m. Solve the following equaion to find the width.
2w+2(10)=30

Answer 1

2(10) = ???

Answer 2

20

Answer 3

so

2w+2(10)=30

2w+20=30

Answer 4

then what

Answer 5

does that mean w=10

Answer 6

no

Answer 7

Can you explain it I really dont get this

Answer 8

2w+2(10)=30

2w+20=30

2w+20-20=30-20

2w=10

2w/2=10/2

w=5


So it's really w = 5