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y varies jointly with p and q. When p = 5 and q = 2, y = 80. Find y when p = 4 and q = 5. a. y = 20 b. y = 120 c. y = 160 d. y = 240
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if y varies jointly with p and q then this implies:\[y=kpq\]where k is some constant. use the given values of p=5, q=2 and y=80 to find k. then use the resulting equation to solve for y.
how do i find k?
you are told that: p=5, q=2 and y=80 - use these values
80 = k10 k = 8
perfect!
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so now you know:\[y=8pq\]
Find y when p = 4 and q = 5.
y = (8)(4)(5) y = 160
great! well done! :)
thank you very much!
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yw :)
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