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Simplify quantity x plus 3 over 9 all over quantity x plus 12 over 6
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\[6x ^{2} + 9 \over 15x ^2\]
over
\[16x-12 \over 10x ^4\]
first, a/b equals a x 1/b , so, use the first one times the reciprocal of the second one
ohh.....I get it
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is the answer 2 open parentheses x plus 3 close parentheses over 3 open parentheses x plus 12 close parentheses
can you draw it, the words are really hard to understand
Next time you have a question like that, using your little notepad, write it like this initially: \[\frac{6x^2 + 9}{15x^2} \div \frac{16x -12}{10x^4}\] That way, you automatically know to take the reciprocal.
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