Question

Use discriminant to determine the number and types of solutions:
1) 3x^2+4x-3=0
2) 4x^2-5x+7=0

Answer 1

I got 2 complex, irrational solutions for both. is that right?

Answer 2

for the second one ...yes...
for first one evaluate discriminant again...:)

Answer 3

two real irrational solutions?

Answer 4

oh sorry wait a sec...

Answer 5

Discriminant of first one : \(16-4*3*(-3)=52\) 2 irrational roots
Discriminant of second one : \(25-4*4*(7)=-87\) 2 complex roots

Answer 6

am i right?

Answer 7

as always..... U r right..

Answer 8

ty :)