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Q(x)=x^5-3x^4+3x^3+x^2-4x+2 Find all of the zeros of Q, real and complex and state the multiplicities
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1 is a root!
-1 too!
so (x+1)(x-1) can be pulled out
but what is a multiplictias?
sec I have to go now for a bit, will be back and try to solve it for the municipalities you need to factor it!
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i will be on it in a sec
(x^2-1)(x^3-3x^2+4x-2)
x^3-3x^2+4x-2 1 is a root again so x^3-3x^2+4x-2=(x-1)(x^2-2x+2)
x^2-2x+2 has roots at 1+i and 1-i
so roots are 1,-1,1+i,1-i all with 1 multi apart from x=1 that has 2 multi
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You have benn a great help, thanks!
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