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The sum of the digits of a two-digit number is 12. If the units digit is 3 times the tens digit, find the number.
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let a be the units digit and b be the tens digit the number = 10b +a to find a and b we must solve the system a+b =12 a= 3b can you solve it ??
I'm not understanding
you dont understand the part that the two digit number = 10b + a ??
I don't understand how we start at 10b+a and then we go to a+b=12
no! these two parts are not related directly.. 10a+b is the general form of any two digits number but a+b =12 is concluded from the given ( The sum of the digits of a two-digit number is 12)
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