Say you had 8 cards. The cards each have one letter on them: Either a G,E,E,M,O,Y,R,T. If you randomly take two cards without replacing the first one before you take the second, find the probability that you will get two E's.

Question

Say you had 8 cards.  The cards each have one letter on them:  Either a G,E,E,M,O,Y,R,T.  If you randomly take two cards without replacing the first one before you take the second, find the probability that you will get two E's.

lgbasallote · Answer

so there are 8 cards all i all

the probability you pick an E card o the first try is 2/8

the probability you pick a second E card is 1/7 (because the first E card has been draw so there's only one E card left and 7 cards left)

so the total probability would be 2/8 x 1/7

does that help?

anonymous · Answer

So it would be .04?

lgbasallote · Answer

is it?..im not sure i dont have a calculator

lgbasallote · Answer

well my google calculator agreed.. it is 0.4 @jadecat

anonymous · Answer

2/8 times 1/7 is not 0.4

anonymous · Answer

It's about 0.04

anonymous · Answer

>>> 2.0/56
0.03571428571428571
>>>