Question

can someone help me with #10 and #11

Answer 1

okay...AC = BD... so, 8x - 3 = 2x + 9...and then. solve for x!

Answer 2

and for #11, it is a similar triangles problem...u will have 2 equations and 2 unknowns...
4x - y = 1
-x + 4 = y
Then solve it!

Answer 3

fo 10 do i add 8x to 2x?

Answer 4

no...u subtract...
i will rearrange for u.. 8x - 2x = 9 + 3
.hopefully, this will make it easier for u...

Answer 5

AC = BD
8x - 2x = 9 + 3
-2x -2x
6x=12
6 6
x=2

Answer 6

is this correct for 10?

Answer 7

how do i solve 11?

Answer 8

@cfraser007

Answer 9

you are correct for 10!

Answer 10

for 11, u have the equations
4x - y = 1
-x + 4 = y
Then, what u can do is simply get that y of the second equation to the left and the 4 to the right and then combine the equations!

Answer 11

so u will have to subtract the equations
then, i think its easy to know what x can be! after that, just put that value of "x" in any of the equations to solve for y!