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How to factor out 5(2x-1)^4+40x(2x-1)^3
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note that \(5(2x-1)^3\) is a common factor \[\large 5(2x-1)^3(2x-1)+5*8x(2x-1)^3\]
\[\large{5(2x-1)^4+40x(2x-1)^3}\] \[\large{5(2x-1)(2x-1)(2x-1)(2x-1)+40x(2x-1)(2x-1)(2x-1)}\] try to take \(\large{5(2x-1)(2x-1)(2x-1)}\) common
K thnx
well can u tell me what r u getting ?
5(2x-1)^3+([2x-1)+4x] =5(2x-1)^3 (6x-1)
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\[\large{5(2x-1)^3(2x-1+8x)}\] \[\large{5(2x-1)^3(10x-1)}\]
How did u got 8x
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