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solve for: d/ dx-> sin^2 (x) - 2 sin x - 3
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Do you want f(x) or f'(x) = 0 or what?
ok its 2 sin x cos x - 2 cos x
is it equal to 0?
yes, it's equal to zero
ok, then 2sinx cos x - 2 cos x = 0 after finding d/dx
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therefore, 2 sinx cos x = 2 cos x
u can cancel out the 2s and a cos x from both sides of the equation
hence we get, sinx = 1
x = pi/2
does it look good?
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was the answer alright?
yes, I couldn't figure it out after I found the derivative, so thnx
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