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what is the standard and general form of y=0.05x^2-x+1
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http://staff.argyll.epsb.ca/jreed/math20p/quadraticFunctions/images/proof_01.gif
can you help by explaining it
In other words, the current form given is General form. Now you have to convert it into Vertex form!
if i follow the formula ill be able to do that?
Yes.
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I started working on the problem and got totally lost. :( Math is my worst subject. Step one: Plug in the numbers into the formula i got y= 0.05(x+ x/290.05)^2 - x^2-4(0.05*1)/4(0.05)
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