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Mathematics 12 Online
OpenStudy (anonymous):

Can someone please help me with this trig problem dealing with logarithms? Click attached

OpenStudy (anonymous):

OpenStudy (lgbasallote):

how is this trig?

OpenStudy (anonymous):

So what it looks like is you just calculate first, right? @lgbasallote good point

OpenStudy (anonymous):

I'm in Precalc/Trig

OpenStudy (anonymous):

@telliott99 Yes, but I need to perform the calculations step by step and I don't know how. That's what I need help with (to be more specific).

OpenStudy (anonymous):

Start with 4.8 x 4.8

OpenStudy (anonymous):

then x 0.073

OpenStudy (anonymous):

then inverse

OpenStudy (anonymous):

23.04*0.073=1.681

OpenStudy (anonymous):

So the inverse of 1.681?

OpenStudy (anonymous):

@telliott99

OpenStudy (anonymous):

So the inverse of 1.681?

OpenStudy (eyust707):

so far we have \[\log_{10}{91.2 \over 1.68192}\]

OpenStudy (eyust707):

then do the division

OpenStudy (eyust707):

91.2/1.68192

OpenStudy (anonymous):

1.734

OpenStudy (eyust707):

no..

OpenStudy (anonymous):

54.2. My bad.

OpenStudy (eyust707):

yep

OpenStudy (eyust707):

\[\log_{10}54.2237 \]

OpenStudy (eyust707):

now type that into a calculator

OpenStudy (anonymous):

1.7341

OpenStudy (anonymous):

Right?

OpenStudy (eyust707):

yep

OpenStudy (anonymous):

So that's it? Thanks so much :)

OpenStudy (eyust707):

no problem =)

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