Mathematics
6 Online
OpenStudy (anonymous):
Please help! Find the common antilogarithm of (7.3139 - 10).
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OpenStudy (anonymous):
what does the -10 mean at the end?
OpenStudy (anonymous):
it's the power to -10 which mean LN
OpenStudy (anonymous):
??
OpenStudy (anonymous):
\(7.3139^{ - 10}\) like that?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
Nope. My problem just states (7.3139-10) like how I posted it
OpenStudy (anonymous):
@godorovg ?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
It's not raised
OpenStudy (anonymous):
what explain further?????
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OpenStudy (anonymous):
... If it was raised I would've ^-10. It's not raised. The problem states:
Find the common logarithm of (7.3139-10).
That's it.
OpenStudy (anonymous):
\(7.3139 - 10=-2.6861\)
OpenStudy (anonymous):
there are choices with answers
OpenStudy (anonymous):
a. .00206
b. .0000206
c. .000206
d. .0206
OpenStudy (anonymous):
this is a negative number and therefore does not have a common log
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OpenStudy (anonymous):
i guess i should just shut up because i clearly do not understand the question
OpenStudy (anonymous):
:(
OpenStudy (anonymous):
ooooh!!!
OpenStudy (anonymous):
the -10 is creating a big trouble here, because of that the answer will be -2 or whatever.
OpenStudy (anonymous):
you don't want the log, you want to raise the power of ten to this number!!
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OpenStudy (anonymous):
\(10^{-2.6861}=0.00206\)
OpenStudy (anonymous):
i mean "raise ten to this power"
OpenStudy (anonymous):
thanks so much I could not recall how to this it is has been a while
OpenStudy (anonymous):
this must be some ancient history math written before they used calculators, when there were log tables
was your book written in like 1964?
OpenStudy (anonymous):
THANK YOU SATELLITE! YOU ARE MY HERO. :) And thank you so much to @godorovg as well for taking the time to help me out!
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OpenStudy (anonymous):
not a problem
OpenStudy (anonymous):
yw
OpenStudy (anonymous):
I wish I could give more than one medal :( @godorovg You really deserve one
OpenStudy (anonymous):
i sent him/her one for you
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OpenStudy (anonymous):
:)
OpenStudy (lgbasallote):
@godorovg didnt i just tell you how to solve this? o.O
OpenStudy (anonymous):
yes sir you dd I wasn't following I feel like a fool lol
OpenStudy (lgbasallote):
lol =))
OpenStudy (lgbasallote):
guess i didnt explain it well a while ago
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OpenStudy (anonymous):
Hey got to admit when you are wrong so I admit it..