Question

7^2x-1= 316. exponential equations...

Answer 1

\[b^x=A\iff x=\frac{\ln(A)}{\ln(b)}\]

Answer 2

\[7^{2x-1}=316\iff 2x-1=\frac{\ln(316)}{\ln(7)}\]

Answer 3

use a calculator to compute the right hand side, then solve for \(x\) by adding one and dividing the result by 2

Answer 4

let me know what you get as a final answer

Answer 5

i got 1.48

Answer 6

then there is a mistake somewhere

Answer 7

i did what you said to do

Answer 8

here is \[\frac{\ln(316)}{\ln(7)}\]
http://www.wolframalpha.com/input/?i=ln%28316%29%2Fln%287%29
is the what you got ?

Answer 9

no

Answer 10

about 2.95866
add 1 to get 3.95866
then divide by 2

Answer 11

perhaps you put it in the calculator wrong
you have to close the parentheses after the log on top

Answer 12

i got 1.979

Answer 13

that is it