Question

Factor the expression completely.

49x^2-81
How do i do thiss?!

Answer 1

Hint:

Use the difference of squares formula

\[\Large a^2 - b^2 = (a-b)(a+b)\]

Answer 2

uhmmm.. what? hahaha

Answer 3

try this :
a^2b^2 - c^2 = (ab + c)(ab - c)

Answer 4

Similar example

\[\Large 36x^2 - 25\]

\[\Large (6x)^2 - 5^2\]

\[\Large (6x-5)(6x+5)\]

So

\[\Large 36x^2 - 25\]

factors to

\[\Large (6x-5)(6x+5)\]

Answer 5

so for mine, it would be 7x^2-9^2?

Answer 6

close, more like (7x)^2 - 9^2

Answer 7

keep going to get ...???

Answer 8

(7x-9)(7x+9)

Answer 9

good

Answer 10

idk what to do for the next part

Answer 11

you're done, it's factored completely

Answer 12

so that's the answer?

Answer 13

yes

Answer 14

(7x-9)(7x+9)?? Okay thanks!

Answer 15

yes, you're welcome