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27^(2x)=9^(x-3), solve for x
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where x is a real number
if i told you that 27 = 3^3 and 9 = 3^2 would that help?
I just want to know what method to use to solve this. You know I'm no good at math...
you use the property \[\huge a^x = a^y \implies x = y\]
is that what you're asking?`
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@haha31896 tell me if you have an answer and want it checked
\[ \huge 27^{(2x)}=9^{(x-3)} \implies 3^ {6x} = 3^{2x-6} \] \[\huge \implies 6x = 2x-6\implies x = -\frac 3 2\]
Okay. I understand..thanks @lgbasallote! That formula you gave helped!
welcome ^_^
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