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logx +log(x-3)=1, solve for x where x is a real number
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start by condensing it..
logx(x-3)=1
good..now change to exponential form
remember..common logs have base 10
x^(2)-3x-10=0, then i factor..
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yup
5 and -2. You're like my official math tutor or something. Thanks for helping me on all these dumb questions I have. I'm sure they are way below your level. :))
haha it's a good way to pass some time ^_^
you're right about 5 and -2 btw
YAY!!
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you're getting good :D
Normally I am way better at math during the school. But during summer break, my brain fries and I forget almost everything. Haha!!
haha yes...everyone gets that feeling =)) i think this site is a great place to learn during summer breaks...rarely gets boring...
definitely!
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