Question

A company builds computers. It costs $7,600 to build 10 computers and $12,200 to build 20 computers. Which equation models the cost, C(x), as a linear function of the number of computers built, x?

C(x) = 460x − 3000

C(x) = 3000x − 460

C(x) = 460x + 3000

C(x) = 3000x + 460

Answer 1

that one is hard............

Answer 2

i know, i dont know what to do...

Answer 3

what if i show u how to do it with another problem

Answer 4

okay

Answer 5

say a is basic cost and b is cost for computer..

so a + 10b = 7600
and a + 20b = 12200

2a + 20b = 15200
a + 20 b = 12200

subtract

a = 3000
and b = 460..

so C(x) = a + xb = 3000 + 460x

Answer 6

oh good job !

Answer 7

thanks !

Answer 8

w/c.. thnx !! :)