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Mathematics 11 Online
OpenStudy (anonymous):

In how many ways can 9 instructors be assigned to seven sections of a course in mathematics?

OpenStudy (mathmate):

Assuming only one instructor per course, and that all course must have instructors. We are choosing 7 instructors out of 9 to teach 7 (different) course sections. For the first section, there are 9 choices, 8 for the second, and so on until the 7th section where there are 3 choices. The total number of ways is therefore 9*8*7*6*....3 =9!/2!

OpenStudy (anonymous):

ok thats what I was thinkn!

OpenStudy (anonymous):

thanks!

OpenStudy (mathmate):

You're welcome! :)

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