Question

Approximate the real number solutions to the polynomial function f(x) = x3 – 4x2 – 4x + 16

Answer 1

f(x) = x^3 - 4x^2 -4x + 16
f(x) = x^2(x-4) -4(x-4)
f(x) = (x-4)(x^2-4)
0 = (x-4)(x^2-4)

x - 4 = 0
x^2 - 4 = 0

x = 4

x^2 = 4
x = ±2

Therefore, 3 solutions