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Mathematics 6 Online
OpenStudy (anonymous):

9. Essay; show all work. A community 5K run will award $50 to the winner. 70 people enter the race, and they each pay an entry fee of $20. Assuming they are all equally likely to win, what is a fair price for the competition? Round to the nearest cent

OpenStudy (lgbasallote):

essay?

OpenStudy (anonymous):

yes it a essay for math

OpenStudy (anonymous):

well if they all pay 20 dollars each then you would multiply by 70 ties 20 and you would get 140. so that means they paid 140 in all so if they when they should get moe than 50 dollars. it is likey that more than one person could win then race at thesame time. so all the people that come across the finish line would have to plit he whole 140.

OpenStudy (shane_b):

\[70*20\neq140 :)\]

OpenStudy (anonymous):

yea it does

OpenStudy (anonymous):

does that sloves your problem and could you become my fan plz because i am a fan of yours

OpenStudy (anonymous):

thank you :)

OpenStudy (anonymous):

your welcome

OpenStudy (shane_b):

No it doesn't. 70*20 = 1400. The fair price would be: \[70x=50\]\[x=$0.71\]

OpenStudy (anonymous):

that's what i got too 1400

OpenStudy (shane_b):

The $1400 doesn't matter really. The fair price (if I'm not mistaken) is the price you charge to break even for the competition (make $0 profit).

OpenStudy (anonymous):

im so sorry bouot that i was writin to ast

OpenStudy (anonymous):

fast

OpenStudy (shane_b):

I figured :)

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

the fair price for the competition would be $0.71 cent

OpenStudy (shane_b):

yes

OpenStudy (anonymous):

thank you guys

OpenStudy (shane_b):

you're welcome :)

OpenStudy (anonymous):

your welcome

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