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Please confirm my answer! Solve for unknown part of triangle: a=22, b=31, c=40. C=96 degrees 30'?
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I see you guys typing but nothing is showing up :/
Which part was the "unknown" part?
C
Which I got 96 degrees 30' but I need a confirmation
There are two unknown angles \[{\sin96 \over 40} = {\sin A \over 22} \] \[22 \sin96 = 40 \sin A\] \[{22 \sin 96 \over 40} = \sin A\] \[\sin^{-1} ({11 \sin96 \over20}) = A\] \[A \approx 33.16 ^{\text o} \]
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So C = 96 degrees, but what is 30'?
a. 96°30' b. 95°0' c. 85°0' d. 83°30' These are the options
eyust707, she only needed to find angle C
I am confused
Oh, I see what the 30' is. 96 degrees, 30 minutes
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ahh
|dw:1344481551635:dw| I'm thinking she was given something similar to this
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