Question

If in triangle ABC, angle C is a right angle, BC = 1 and tan angle B = p, then cos angle A =
(a) 1/ (square root (p^2 + 1))
(b) p/p+1
(c) p/(square root (p^2 + 1))
(d) (square root (p^2 + 1))/ p
(e) p^2 + 1

Answer 1

maybe draw the triangle first..

Given:

Answer 2

then according to pythagoran theorem...