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16 < 3x + 1 < 4 Part 1: Solve the inequality above. Part 2: Describe the graph of the solution.
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\[ 16 < 3x + 1 < 4 ==> \]This is not possible, if it's not a typo then:15 < 3x < 35 < x < 1 ==> This is an impossible outcome, there is no solution. But if it is: \[4 < 3x + 1 < 16 \\ 3 < 3x < 15 \\ 1 < x < 5\] interval notation: (1 , 5)
yup what she said lol (:
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