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Mathematics 13 Online
OpenStudy (anonymous):

Based on the cards shown below, what is P(odd and red)?

OpenStudy (anonymous):

OpenStudy (anonymous):

2/5? or is it 3/5,... confused.

OpenStudy (unklerhaukus):

how many of the cards are odd,

OpenStudy (unklerhaukus):

and of these, how many are red?

OpenStudy (anonymous):

odd=3 red=2

OpenStudy (unklerhaukus):

how many are ,, odd AND red

OpenStudy (anonymous):

\[P(Odd \; \And \; Red) = P(Odd) + P(Red) - P(Odd \;Or \;Red)\]

OpenStudy (anonymous):

2?

OpenStudy (anonymous):

How ??

OpenStudy (anonymous):

They should be ODD And RED also..

OpenStudy (anonymous):

Are both REDs are ODD ??

OpenStudy (anonymous):

no

OpenStudy (anonymous):

IM SO CONFUSED.....

OpenStudy (anonymous):

Nothing of the REDs are ODD.. So probability will be 0..

OpenStudy (anonymous):

ohhh.. :P ok thanks.

OpenStudy (unklerhaukus):

none are odd and red

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