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solve for: 2 sinx - sin 2x = 0
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sin 2x = 2sinx cosx 2sinx - 2sinx cosx = 0 2sinx (1 - cosx) =0
so u have Two cases
2sinx =0 ------>1 1-cosx =0 ------>2
just solve !!.... hope this helps u
how did you get the "cos x" out of 2 sin x?
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just take the common term outside.... distributive law
no mean, on the first line you have : sin 2x = 2sinx cosx where did that cos x come from :s
it is just a formula
ow oke, thnx :D
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