Question

Write C++ prgm to find the sqrt of a number using functions?

Answer 1

Here it is :

#include<stdio.h>
#include<stdlib.h>
#include<math.h>

int main() {
int x; //Declare a variable.
printf("Enter a number : "); // A small message
scanf("%d", &x); //Get the value entered by the user.
printf("SQRT = %f\n", sqrt(x)); // Use the predifined function sqrt(),
// in the library math.h, and print out the result.
system("pause");
}

Good luck.

Answer 2

#include<iostream>
#include<cmath>
#include<iomanip>

int main()
{
cout<<fixed<<setprecision(2)<<endl;
double number;
cout<<"Enter the number i'll give you the square root : "
cin>>number;

cout<<"The square root is "<<sqrt(number)<<endl;

return 0;


}

Answer 3

#include <iostream>
using namespace std;

void input(int &num);
void find_sqrt(const int num,int &sqrt_no);
void output(const int num,const int sqrt_no);

int main ()
{
int sqrt_no=1,num=1;

input(num);
find_sqrt(num,sqrt_no);
output(num,sqrt_no);

return 0;
}

void input(int &num)
{
cout<<"Please Enter Positive Integer: ";
cin>>num;
}

void output(const int num,const int sqrt_no)
{
if(sqrt_no*sqrt_no==num)
cout<<"Square Root is "<<sqrt_no<<endl;
else
cout<<"Square Root is Not found"<<endl;
}

void find_sqrt(const int num,int &sqrt_no)
{
for(sqrt_no=0;sqrt_no<=num/2;sqrt_no++)
{
if(sqrt_no*sqrt_no==num)
break;
}
}