Question

Please sole them , and check if my answers are right :

1/(|x|-3) < 1/2 .. Ans : x > 5 ; x < -5

Answer 1

u did it well...but there is a little point

everytime u want to solve a equation or inequality firstly consider ristrictions...
for example here the denum of LHS cant be zero otherwise u have division by zero and that is not allowed so\[|x|-3 \neq0 \rightarrow |x| \neq3 \rightarrow x \neq \pm3\]