Question

For the equation x2 + 3x + j = 0, find all the values of j such that the equation has two real number solutions. Show your work.

Answer 1

ax^2 + bx + c = 0

for two real roots b^2 - 4ac >= 0
so for your equation
3^2 - 4*1*j >= 0
4j <= 9
j <= 9/4

- this includes 2 real equal roots

for 2 real unequal roots we have
j < 9/4

Answer 2

ok?