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I need some Math help please.... Indicate in standard form the equation of the line passing through the given points. R(3, 3), S(-6, -6)
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use the formula \[\Large y - y_1 = \frac{y_2 - y_1}{x_2 - x_1} (x-x_1)\] does that help?
I got... Y-3=-9 over 9=X-3
close... \[\Large \frac{y_2 - y_1}{x_2 - x_1} \implies \frac{-6 - 3}{-6 - 3} \implies \frac{-9}{-9} \implies 1\] so the equation should be something like y - 3 = 1(x-3) do you get it?
Yeah. So that's the answer?
not yet. simplify it
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Now I'm lost. I have no idea how to simplify it.
what's 1(x-3)?
I don't know. Distributive property?
yup
So.. is the answer 1x-3?
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right.. y - 3 = x- 3 now add 3 to both sides
Alright man, thanks I appreciate the help!
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