Question

If (a^x)^2/3 = 1/a^2, then x =
(a) -1
(b) -2
(c) -3
(d) 2
(e) 1

Answer 1

\[(a^x)^{2/3} = \frac{1}{a^2}\]
\[\implies a^{2x/3} = a^{-2}\]
therefore\[\frac{2x}3 = -2\]
\[2x = -2 \times 3\]
\[2x = -6\]
\\[x = \frac{-6}2\]
\[x = -3\]
does that help?

Answer 2

yesss thanks :)

Answer 3

welcome