Question

The measure of the length of a room is 13a – 3b inches and the measure of the width of the room is a + 2b feet. Find a simplified expression for its perimeter.

Answer 1

im assuming the room is rectangular?

Answer 2

\[P = l + l + w + w\]
\[P = (13a - 3b) + (13a - 3b) + (a+2b) + (a+2b)\]
\[\implies 13a - 3b + 13a - 3b+a + 2b + a + 2b\]
\[\implies 26a - 6b + 2a + 4b\]
\[\implies 28a - 2b\]
does that help?

Answer 3

yes thank yu!!!!

Answer 4

welcome