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If one solution for x^3 + 2x^2 + x+ 2 is i, where i = radical -1, which of the following sets contains all other solutions? (a) (-i) (b) (-i, 2) (c) (-i, -2) (d) (2, -2) (e) (2)
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if \(i\) is a solution of your equation, then also \(-i\) is a solution
so we can eliminate (d) and (e)
and (a)
so u gotta choose between 2 or -2
yes but how
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replace x=2 and x=-2 and see which one makes the polynomial zero.
got it. 2 doesn't work but -2 does, so the answer's (c)
thanks
u r w
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