Question

The figure below shows segments AC and EF which intersect at point B. Segment AF is parallel to segment EC.



Which of these facts is used to prove that triangle ABF is similar to triangle CBE?

Angle FAB is equal to angle CEB because corresponding angles are congruent.

Angle ABF is congruent to angle CEB because vertically opposite angles are congruent.

Angle AFB is congruent to angle CEB because alternate interior angles are congruent.

Angle AFB is congruent to angle CEB because supplementary angles are congruent.

Answer 1

http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_1000_Subtest_03_11/image0014e8c7e7b.jpg

Answer 2

angle A = angle C
angle F = angle E
because of some line through parallel lines postulate

Answer 3

Thank you!!!! :)

Answer 4

i dont remember the actual postulate or theorem name, but im going to assume you know the actual name for t

Answer 5

what was it?