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help with this one now please
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it says p(not blue)
...blurred...
........wear glasses.......
lol. nice trolling.
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it says given the table M&M distributions below, find p(not blue), the probability of selecting anything but blue from M&M at random from large bag
since prob of selecting is 0.24,prob of not selecting will be 1-0.24 which is 0.76....and ? should be replaced by 0.14 as total sum has to be 1....
thank youu!
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