Question

What shall I put wherein
in the else statement the program will end if the scanned answer is not a 'Y' or a 'y'

Answer 1

in c++ you can write
if(dummy==121||dummy=89)//dummy is character type variable,just for ur understanding
break;

Y has ascii of 89 and y has 89+32=121

actually u can get ur solution by using ascii or simply as

if(dummy=='Y' || dummy== 'y')
break;

Answer 2

we were not allowed to do such thing ... any other ways???

Answer 3

do u know if-statement? and is it allowed?
m not asking about compound if statement)