Question

you toss 2 coins. find P(at least 1 tail is tossed)

Answer 1

P( no tail ) = 1/2*1/2=1/4
So P( at least 1 tail) is the opposite case of that

Answer 2

(H,H) , (T,T) , (H,T) , (T.H) ==== POSSIBLE OUTCOMES

Answer 3

1-P(none is tails)=1-(P(1st is head)and P(2nd is head))....=1-0.5*0.5

Answer 4

so its 0.5?

Answer 5

no....1-0.5*0.5=1-0.25=0.75 or 3/4

Answer 6

2 coins possible outcomes are:

Heads, Tails
Tails, Heads
Heads, Heads
Tails, Tails

Therefore, the probability of at least 1 tail from 2 coins is tossed is 3/4.