Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

Factor completely: 2x3y4 − 8x2y3 + 6xy2 2(x3y4 − 4x2y3 + 3xy2) 2x(x2y4 − 4xy3 + 3y2) 2xy2(x2y2 − 4xy + 3) Prime

OpenStudy (amistre64):

what wrong with the options as stated?

OpenStudy (amistre64):

first one, everyting still has at least an x and a y in common; so it aint factored all the way second one, still has at least a y in common, so it aint factored all the way third one looks like there are no more common factors, its a possibility last option is absurd since there are obviously common factors

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!