Question

Factor completely: 18x2 − 21x − 15

3(2x + 1)(3x − 5)

3(2x − 5)(3x + 1)

3(2x − 1)(3x + 5)

3(6x + 1)(x − 5)

Answer 1

18x^2-21x-15=3(6x^2-7x-5)=3{6x^2-10x+3x-5)

Answer 2

now can u?

Answer 3

well it can be written this way as 3(6x^2-7x-5)
as w are taking out the common
next break the middle term
can you do it now?

Answer 4

WAIT WHAT

Answer 5

see after taking out the common of the equation you will get 6x^2-7x-5
then you are going to break the middle term ie 7x in such a way that when you multiply yo get 30 and if you add or sub you get 7x
so we will get (6x^2-10x+3x-5)
now you got it?

Answer 6

OK YES

Answer 7

so is it D?