Question

in real numbers \[a-b-c+d=1\]\[a^2+b^2-c^2-d^2=3\]\[a^3-b^3-c^3+d^3=-5\]\[a^4+b^4-c^4-d^4=15\]

Answer 1

@experimentX

Answer 2

what in the world .. ??

Answer 3

dont have any idea

Answer 4

now this seems a real challenge!

Answer 5

by the what are we supposed to do????????

Answer 6

system of Diophantine eqn??

Answer 7

no real numbers

Answer 8

What is your question ??

Answer 9

solve the system of equations above in real numbers

Answer 10

a non linear system ... Man this is crazy!!

Answer 11

i would ask wolf ... lol

Answer 12

yeah really crazy...

Answer 13

Can't it be more difficult @mukushla

Answer 14

i asked wolf ... the answer is nice. all integer solution.

Answer 15

Is the answer unique?

Answer 16

2 answers

Answer 17

(1,2,-1,-1) and (-2,...i cant remember)

Answer 18

Only two?

Answer 19

yeah

Answer 20

http://www.wolframalpha.com/input/?i=a%E2%88%92b%E2%88%92c%2Bd%3D1%3B+a^2%2Bb^2%E2%88%92c^2%E2%88%92d^2%3D3%3B+a^3%E2%88%92b^3%E2%88%92c^3%2Bd^3%3D%E2%88%925%3B+a^4%2Bb^4%E2%88%92c^4%E2%88%92d^4%3D15