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Mathematics 24 Online
OpenStudy (anonymous):

What polynomial has roots of -1, -2, and 3

OpenStudy (anonymous):

x3 + 6x2 + 11x + 6 x3 - x2 - 5x + 2 x3 + 2x2 - 7x + 2 x3 - 7x - 6

OpenStudy (amistre64):

a(x-r1)(x-r2)(x-r3)

Parth (parthkohli):

Factor theorem. The possible factors are: (x - (-1)) (x - (-2)) (x - (-3)) Multiply the factors together.

OpenStudy (anonymous):

I don't understand

OpenStudy (anonymous):

I multiply x ans 1?

OpenStudy (amistre64):

f(r) = 0 if f(x) has those roots is another method to check

OpenStudy (anonymous):

so it is x3 - x2 - 5x + 2

OpenStudy (amistre64):

x3 - x2 - 5x + 2 0 -1 2 3 -1 1 -2 -3 5 not 0 not that one

OpenStudy (amistre64):

-1 -1 +5 +2 = 5, so -1 aint a root and it needs to be

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