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What polynomial has roots of -1, -2, and 3
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x3 + 6x2 + 11x + 6 x3 - x2 - 5x + 2 x3 + 2x2 - 7x + 2 x3 - 7x - 6
a(x-r1)(x-r2)(x-r3)
Factor theorem. The possible factors are: (x - (-1)) (x - (-2)) (x - (-3)) Multiply the factors together.
I don't understand
I multiply x ans 1?
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f(r) = 0 if f(x) has those roots is another method to check
so it is x3 - x2 - 5x + 2
x3 - x2 - 5x + 2 0 -1 2 3 -1 1 -2 -3 5 not 0 not that one
-1 -1 +5 +2 = 5, so -1 aint a root and it needs to be
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