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Mathematics 7 Online
OpenStudy (anonymous):

Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a green marble, replacing it, and then picking a brown marble?

OpenStudy (anonymous):

4/19 to pick one green

OpenStudy (anonymous):

1/19 to pick brown

OpenStudy (anonymous):

so it would be 1/9?

OpenStudy (anonymous):

Multiply those together

OpenStudy (anonymous):

Actually I don't think that's correct

OpenStudy (anonymous):

i get 0.0058 on the calculator

OpenStudy (anonymous):

hmm..how do i calculate it?

OpenStudy (anonymous):

Is ur option a fraction or decimal

OpenStudy (anonymous):

frac

OpenStudy (anonymous):

Is 5/19 a option?

OpenStudy (anonymous):

i dont have options..

OpenStudy (anonymous):

I think it's 5/19 u just add them , since they have common denominator

OpenStudy (anonymous):

19 marbles , 5 green and 1 brown

OpenStudy (anonymous):

Sorry 4 green

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

4/19+1/19

OpenStudy (anonymous):

Yw lol so what flavor coolaid ??

OpenStudy (anonymous):

haha...i like grape.

OpenStudy (anonymous):

Lmao mmmm tropical punch for me

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