Question

solve: x^2+5x-3=0

Answer 1

use \[D^2=(b ^{2}-4*a*c)/2a\]

Answer 2

kks thanks

Answer 3

\[x^2+5x-3=0\]
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with
\[a=1, b=5,c=-3\]

Answer 4

you get
\[x=\frac{-5\pm\sqrt{(-5)^2-4\times 1\times (-3)}}{2\times 1}\] then some careful arithmetic to get your answer