IM ON THE LAST QUESTION TILL FREEDOM FROM GEOMETRY!!!!!!!!! A quadrilateral EFGH has coordinates E (-1, -2), F (5, -2), G (5, -8) and H (-1, -8). Quadrilateral EFGH has diagonals that are unequal diagonals that do not bisect all four sides equal opposite sides unequal
i really need help i tried drawing it on a grid but it makes no sense to me
see without solving you can find answer by plotting it on graph....
i am im doing it right now:) but i dont think im right i got B but that cant be right can u check cuz i really dont want to fail
it's C
how?-_-
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it's a rough sketch ...try to plot it on graph paper..you'll get all sides = 6
and to verify it you can use distance formula between different coordinates to calculate the sides of quadrilateral.... \[d=\sqrt{(x2-x1)^2+(y2-y1)^2}\]
you'll get all sides = 6
oh ok hmmm i guess i graphed wrong or something but thatnk u sooooo much:)
thank you:)
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