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OpenStudy (anonymous):
Solve the proportion x/x^2-2 = 2/3x +5 What is the value of x?
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OpenStudy (ghazi):
go for the cross multiplication...
OpenStudy (ghazi):
x(3x+5)=2(x^2-2).....3x^2+5x=2x^2-4...now rearrange and solve for x
OpenStudy (anonymous):
How would you rearrange that?
OpenStudy (ghazi):
3x^2-2x^2+5x+4=0
OpenStudy (ghazi):
that means X^2+5X+4=0 therefore (x+4)(x+1)=0...now you can find x
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OpenStudy (anonymous):
Okay, thanks :)
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